Integrand size = 17, antiderivative size = 17 \[ \int \frac {1}{\sqrt {b x} \sqrt {4+b x}} \, dx=\frac {2 \text {arcsinh}\left (\frac {\sqrt {b x}}{2}\right )}{b} \]
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Time = 0.00 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {65, 221} \[ \int \frac {1}{\sqrt {b x} \sqrt {4+b x}} \, dx=\frac {2 \text {arcsinh}\left (\frac {\sqrt {b x}}{2}\right )}{b} \]
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Rule 65
Rule 221
Rubi steps \begin{align*} \text {integral}& = \frac {2 \text {Subst}\left (\int \frac {1}{\sqrt {4+x^2}} \, dx,x,\sqrt {b x}\right )}{b} \\ & = \frac {2 \sinh ^{-1}\left (\frac {\sqrt {b x}}{2}\right )}{b} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(44\) vs. \(2(17)=34\).
Time = 0.05 (sec) , antiderivative size = 44, normalized size of antiderivative = 2.59 \[ \int \frac {1}{\sqrt {b x} \sqrt {4+b x}} \, dx=\frac {4 \sqrt {x} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {x}}{-2+\sqrt {4+b x}}\right )}{\sqrt {b} \sqrt {b x}} \]
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Time = 0.68 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.35
method | result | size |
meijerg | \(\frac {2 \sqrt {x}\, \operatorname {arcsinh}\left (\frac {\sqrt {b}\, \sqrt {x}}{2}\right )}{\sqrt {b}\, \sqrt {b x}}\) | \(23\) |
default | \(\frac {\sqrt {b x \left (b x +4\right )}\, \ln \left (\frac {b^{2} x +2 b}{\sqrt {b^{2}}}+\sqrt {b^{2} x^{2}+4 b x}\right )}{\sqrt {b x}\, \sqrt {b x +4}\, \sqrt {b^{2}}}\) | \(60\) |
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none
Time = 0.22 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.47 \[ \int \frac {1}{\sqrt {b x} \sqrt {4+b x}} \, dx=-\frac {\log \left (-b x + \sqrt {b x + 4} \sqrt {b x} - 2\right )}{b} \]
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Time = 0.64 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int \frac {1}{\sqrt {b x} \sqrt {4+b x}} \, dx=\frac {2 \operatorname {asinh}{\left (\frac {\sqrt {b} \sqrt {x}}{2} \right )}}{b} \]
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Leaf count of result is larger than twice the leaf count of optimal. 32 vs. \(2 (13) = 26\).
Time = 0.26 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.88 \[ \int \frac {1}{\sqrt {b x} \sqrt {4+b x}} \, dx=\frac {\log \left (2 \, b^{2} x + 2 \, \sqrt {b^{2} x^{2} + 4 \, b x} b + 4 \, b\right )}{b} \]
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none
Time = 0.31 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.24 \[ \int \frac {1}{\sqrt {b x} \sqrt {4+b x}} \, dx=-\frac {2 \, \log \left (\sqrt {b x + 4} - \sqrt {b x}\right )}{b} \]
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Time = 0.33 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.94 \[ \int \frac {1}{\sqrt {b x} \sqrt {4+b x}} \, dx=-\frac {4\,\mathrm {atan}\left (\frac {b\,\left (\sqrt {b\,x+4}-2\right )}{\sqrt {b\,x}\,\sqrt {-b^2}}\right )}{\sqrt {-b^2}} \]
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